Exercise Lover

March 9, 2007

Exercises A.1-1

Filed under: A.1 — yuhanlyu @ 5:19 pm

\sum^n_{k=1} (2k-1)
= 2 \sum^n_{k=1}k - \sum^n_{k=1} 1
= n(n+2)

1 Comment »

  1. The answer to this is n^2. I dunno what k(k + 2) is about.

    Comment by Xeno — April 11, 2008 @ 5:04 am


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